Ordering Elements of a List<String> by Length and Content

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Here’s how to order the elements of a List<String> first by length and then by content

C#

static void Main(string[] args)
{
    IEnumerable<string> newList = null;

    List<string> strList = new List<string>()
    {
        "Jane", "Bandy", "Ram", "Fiddo", "Carol"
    };

    newList = strList.OrderBy(x => x.Length)
                    .ThenByDescending(x => x);

    foreach (var str in newList)
        Console.WriteLine(str);
    Console.ReadLine();
}

VB.NET

Shared Sub Main(ByVal args() As String)
    Dim newList As IEnumerable(Of String) = Nothing

    Dim strList As New List(Of String)() From _

{"Jane", "Bandy", "Ram", "Fiddo", "Carol"}

    newList = strList.OrderBy(Function(x) x.Length)_

.ThenByDescending(Function(x) x)

    For Each str In newList
        Console.WriteLine(str)
    Next str
    Console.ReadLine()
End Sub

OUTPUT

You can also read Some Common Operations using List<string>

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About The Author

Suprotim Agarwal, Developer Technologies MVP (Microsoft Most Valuable Professional) is the founder and contributor for DevCurry, DotNetCurry and SQLServerCurry. He is the Chief Editor of a Developer Magazine called DNC Magazine. He has also authored two Books - 51 Recipes using jQuery with ASP.NET Controls. and The Absolutely Awesome jQuery CookBook.

Follow him on twitter @suprotimagarwal.